Base | Representation |
---|---|
bin | 1011111011010101111101… |
… | …0000000110010101001011 |
3 | 1201102200212111021100110211 |
4 | 2332311133100012111023 |
5 | 3204330221100213233 |
6 | 43520314415221551 |
7 | 2522315306030146 |
oct | 276653720062513 |
9 | 51380774240424 |
10 | 13114133210443 |
11 | 41a6744349001 |
12 | 15797348178b7 |
13 | 741871577875 |
14 | 334a2811705d |
15 | 17b1de5695cd |
hex | bed5f40654b |
13114133210443 has 2 divisors, whose sum is σ = 13114133210444. Its totient is φ = 13114133210442.
The previous prime is 13114133210419. The next prime is 13114133210459. The reversal of 13114133210443 is 34401233141131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13114133210443 is a prime.
It is a super-2 number, since 2×131141332104432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13114133210413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557066605221 + 6557066605222.
It is an arithmetic number, because the mean of its divisors is an integer number (6557066605222).
Almost surely, 213114133210443 is an apocalyptic number.
13114133210443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114133210443 is an equidigital number, since it uses as much as digits as its factorization.
13114133210443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 13114133210443 its reverse (34401233141131), we get a palindrome (47515366351574).
The spelling of 13114133210443 in words is "thirteen trillion, one hundred fourteen billion, one hundred thirty-three million, two hundred ten thousand, four hundred forty-three".
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