1311414001 has 2 divisors, whose sum is σ = 1311414002. Its totient is φ = 1311414000.

The previous prime is 1311413993. The next prime is 1311414031. The reversal of 1311414001 is 1004141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1142440000 + 168974001 = 33800^2 + 12999^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311414001 - 2³ = 1311413993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311414031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655707000 + 655707001.

It is an arithmetic number, because the mean of its divisors is an integer number (655707001).

Almost surely, 2^1311414001 is an apocalyptic number.

It is an amenable number.

1311414001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311414001 is an equidigital number, since it uses as much as digits as its factorization.

1311414001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1311414001 is about 36213.4505536272. The cubic root of 1311414001 is about 1094.5777236513.

Adding to 1311414001 its reverse (1004141131), we get a palindrome (2315555132).

The spelling of 1311414001 in words is "one billion, three hundred eleven million, four hundred fourteen thousand, one".