13114140322057 has 2 divisors, whose sum is σ = 13114140322058. Its totient is φ = 13114140322056.

The previous prime is 13114140322043. The next prime is 13114140322117. The reversal of 13114140322057 is 75022304141131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12784171646016 + 329968676041 = 3575496^2 + 574429^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114140322057 - 2¹¹ = 13114140320009 is a prime.

It is a super-2 number, since 2×13114140322057² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13114140722057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557070161028 + 6557070161029.

It is an arithmetic number, because the mean of its divisors is an integer number (6557070161029).

Almost surely, 2^{13114140322057} is an apocalyptic number.

It is an amenable number.

13114140322057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114140322057 is an equidigital number, since it uses as much as digits as its factorization.

13114140322057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 13114140322057 its reverse (75022304141131), we get a palindrome (88136444463188).

The spelling of 13114140322057 in words is "thirteen trillion, one hundred fourteen billion, one hundred forty million, three hundred twenty-two thousand, fifty-seven".