Base | Representation |
---|---|
bin | 11101110100010110111100… |
… | …110011010010011001001011 |
3 | 122012022222212221000200201121 |
4 | 131310112330303102121023 |
5 | 114142110043411310214 |
6 | 1142525310155100111 |
7 | 36423440146543552 |
oct | 3564267463223113 |
9 | 565288787020647 |
10 | 131141404010059 |
11 | 38870836794853 |
12 | 128600baa41637 |
13 | 58237732667a1 |
14 | 24553c64aad99 |
15 | 102644ee19424 |
hex | 7745bccd264b |
131141404010059 has 2 divisors, whose sum is σ = 131141404010060. Its totient is φ = 131141404010058.
The previous prime is 131141404010039. The next prime is 131141404010129. The reversal of 131141404010059 is 950010404141131.
It is a weak prime.
It is an emirp because it is prime and its reverse (950010404141131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131141404010059 - 215 = 131141403977291 is a prime.
It is not a weakly prime, because it can be changed into another prime (131141404010009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570702005029 + 65570702005030.
It is an arithmetic number, because the mean of its divisors is an integer number (65570702005030).
Almost surely, 2131141404010059 is an apocalyptic number.
131141404010059 is a deficient number, since it is larger than the sum of its proper divisors (1).
131141404010059 is an equidigital number, since it uses as much as digits as its factorization.
131141404010059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 34.
The spelling of 131141404010059 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred four million, ten thousand, fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •