131141404146131 has 2 divisors, whose sum is σ = 131141404146132. Its totient is φ = 131141404146130.

The previous prime is 131141404146127. The next prime is 131141404146211. The reversal of 131141404146131 is 131641404141131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131141404146131 - 2² = 131141404146127 is a prime.

It is a super-2 number, since 2×131141404146131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131141404146091 and 131141404146100.

It is not a weakly prime, because it can be changed into another prime (131141404146931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570702073065 + 65570702073066.

It is an arithmetic number, because the mean of its divisors is an integer number (65570702073066).

Almost surely, 2^{131141404146131} is an apocalyptic number.

131141404146131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141404146131 is an equidigital number, since it uses as much as digits as its factorization.

131141404146131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 35.

Adding to 131141404146131 its reverse (131641404141131), we get a palindrome (262782808287262).

The spelling of 131141404146131 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred four million, one hundred forty-six thousand, one hundred thirty-one".