13114201124147 has 2 divisors, whose sum is σ = 13114201124148. Its totient is φ = 13114201124146.

The previous prime is 13114201124137. The next prime is 13114201124153. The reversal of 13114201124147 is 74142110241131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13114201124147 - 2⁶ = 13114201124083 is a prime.

It is a super-2 number, since 2×13114201124147² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13114201124137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557100562073 + 6557100562074.

It is an arithmetic number, because the mean of its divisors is an integer number (6557100562074).

Almost surely, 2^{13114201124147} is an apocalyptic number.

13114201124147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114201124147 is an equidigital number, since it uses as much as digits as its factorization.

13114201124147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 32.

Adding to 13114201124147 its reverse (74142110241131), we get a palindrome (87256311365278).

The spelling of 13114201124147 in words is "thirteen trillion, one hundred fourteen billion, two hundred one million, one hundred twenty-four thousand, one hundred forty-seven".