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131142102967643 is a prime number
BaseRepresentation
bin11101110100010111100110…
…011101100110010101011011
3122012100001200122020102021112
4131310113212131212111123
5114142113011324431033
61142525503404130535
736423463364564015
oct3564274635462533
9565301618212245
10131142102967643
1138871065291a49
1212860274b36a4b
135823854ccc561
1424554512531b5
151026491482c48
hex7745e676655b

131142102967643 has 2 divisors, whose sum is σ = 131142102967644. Its totient is φ = 131142102967642.

The previous prime is 131142102967591. The next prime is 131142102967669. The reversal of 131142102967643 is 346769201241131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131142102967643 - 210 = 131142102966619 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 131142102967591 and 131142102967600.

It is not a weakly prime, because it can be changed into another prime (131142102967243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051483821 + 65571051483822.

It is an arithmetic number, because the mean of its divisors is an integer number (65571051483822).

Almost surely, 2131142102967643 is an apocalyptic number.

131142102967643 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142102967643 is an equidigital number, since it uses as much as digits as its factorization.

131142102967643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 131142102967643 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred two million, nine hundred sixty-seven thousand, six hundred forty-three".