Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …011110111010010001011001 |
3 | 122012100001200122212212220002 |
4 | 131310113212132322101121 |
5 | 114142113011421431244 |
6 | 1142525503415342345 |
7 | 36423463400525246 |
oct | 3564274636722131 |
9 | 565301618785802 |
10 | 131142103311449 |
11 | 388710654a728a |
12 | 128602750819b5 |
13 | 58238550bcba9 |
14 | 24554513025cd |
15 | 10264914eea4e |
hex | 7745e67ba459 |
131142103311449 has 2 divisors, whose sum is σ = 131142103311450. Its totient is φ = 131142103311448.
The previous prime is 131142103311389. The next prime is 131142103311463. The reversal of 131142103311449 is 944113301241131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116505686688400 + 14636416623049 = 10793780^2 + 3825757^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131142103311449 is a prime.
It is not a weakly prime, because it can be changed into another prime (131142103311049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571051655724 + 65571051655725.
It is an arithmetic number, because the mean of its divisors is an integer number (65571051655725).
Almost surely, 2131142103311449 is an apocalyptic number.
It is an amenable number.
131142103311449 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142103311449 is an equidigital number, since it uses as much as digits as its factorization.
131142103311449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 38.
The spelling of 131142103311449 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred three million, three hundred eleven thousand, four hundred forty-nine".
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