131142114213001 has 4 divisors (see below), whose sum is σ = 131143312503504. Its totient is φ = 131140915922500.

The previous prime is 131142114212981. The next prime is 131142114213023. The reversal of 131142114213001 is 100312411241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131142114213001 - 2⁹ = 131142114212489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131142114217001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598981075 + ... + 599199976.

It is an arithmetic number, because the mean of its divisors is an integer number (32785828125876).

Almost surely, 2^{131142114213001} is an apocalyptic number.

It is an amenable number.

131142114213001 is a deficient number, since it is larger than the sum of its proper divisors (1198290503).

131142114213001 is a wasteful number, since it uses less digits than its factorization.

131142114213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1198290502.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131142114213001 its reverse (100312411241131), we get a palindrome (231454525454132).

The spelling of 131142114213001 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred fourteen million, two hundred thirteen thousand, one".