131142130402201 has 4 divisors (see below), whose sum is σ = 131163625594404. Its totient is φ = 131120635210000.

The previous prime is 131142130402147. The next prime is 131142130402223. The reversal of 131142130402201 is 102204031241131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 43004281795225 + 88137848606976 = 6557765^2 + 9388176^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142130402201 - 2²¹ = 131142128305049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131142130402271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10747586950 + ... + 10747599151.

It is an arithmetic number, because the mean of its divisors is an integer number (32790906398601).

Almost surely, 2^{131142130402201} is an apocalyptic number.

It is an amenable number.

131142130402201 is a deficient number, since it is larger than the sum of its proper divisors (21495192203).

131142130402201 is an equidigital number, since it uses as much as digits as its factorization.

131142130402201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21495192202.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131142130402201 its reverse (102204031241131), we get a palindrome (233346161643332).

The spelling of 131142130402201 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty million, four hundred two thousand, two hundred one".