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131142132344417 is a prime number
BaseRepresentation
bin11101110100010111101000…
…001101101010011001100001
3122012100001202200111220122012
4131310113220031222121201
5114142113041340010132
61142525510333522305
736423464202355415
oct3564275015523141
9565301680456565
10131142132344417
113887107a927177
1212860282943395
13582385b11696c
1424554550dcd45
151026493d370b2
hex7745e836a661

131142132344417 has 2 divisors, whose sum is σ = 131142132344418. Its totient is φ = 131142132344416.

The previous prime is 131142132344341. The next prime is 131142132344423. The reversal of 131142132344417 is 714443231241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120375655469056 + 10766476875361 = 10971584^2 + 3281231^2 .

It is a cyclic number.

It is not a de Polignac number, because 131142132344417 - 210 = 131142132343393 is a prime.

It is a super-2 number, since 2×1311421323444172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131142132344117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571066172208 + 65571066172209.

It is an arithmetic number, because the mean of its divisors is an integer number (65571066172209).

Almost surely, 2131142132344417 is an apocalyptic number.

It is an amenable number.

131142132344417 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142132344417 is an equidigital number, since it uses as much as digits as its factorization.

131142132344417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 193536, while the sum is 41.

Adding to 131142132344417 its reverse (714443231241131), we get a palindrome (845585363585548).

The spelling of 131142132344417 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty-two million, three hundred forty-four thousand, four hundred seventeen".