Base | Representation |
---|---|
bin | 10011000101010110110… |
… | …111011100101000011101 |
3 | 11122101000021121112210000 |
4 | 103011112313130220131 |
5 | 132441243113313203 |
6 | 2442243101204513 |
7 | 163514161325232 |
oct | 23052667345035 |
9 | 4571007545700 |
10 | 1311422401053 |
11 | 466197836166 |
12 | 1921b4860739 |
13 | 968886a762b |
14 | 4768a5b1789 |
15 | 241a6b004a3 |
hex | 13156ddca1d |
1311422401053 has 20 divisors (see below), whose sum is σ = 1986630500448. Its totient is φ = 861967771560.
The previous prime is 1311422401033. The next prime is 1311422401099. The reversal of 1311422401053 is 3501042241131.
1311422401053 is a `hidden beast` number, since 1 + 311 + 4 + 2 + 240 + 105 + 3 = 666.
It is not a de Polignac number, because 1311422401053 - 28 = 1311422400797 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311422401033) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 114011151 + ... + 114022652.
Almost surely, 21311422401053 is an apocalyptic number.
It is an amenable number.
1311422401053 is a deficient number, since it is larger than the sum of its proper divisors (675208099395).
1311422401053 is an equidigital number, since it uses as much as digits as its factorization.
1311422401053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228033886 (or 228033877 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 1311422401053 its reverse (3501042241131), we get a palindrome (4812464642184).
The spelling of 1311422401053 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, four hundred one thousand, fifty-three".
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