Base | Representation |
---|---|
bin | 1011111011010110010010… |
… | …1010011110111111111011 |
3 | 1201102201002211010121120212 |
4 | 2332311210222132333323 |
5 | 3204330412321411212 |
6 | 43520331421341335 |
7 | 2522320460605424 |
oct | 276654452367773 |
9 | 51381084117525 |
10 | 13114224013307 |
11 | 41a679062859a |
12 | 157975b10784b |
13 | 74188731b081 |
14 | 334a361d264b |
15 | 17b1e7503e22 |
hex | bed64a9effb |
13114224013307 has 2 divisors, whose sum is σ = 13114224013308. Its totient is φ = 13114224013306.
The previous prime is 13114224013159. The next prime is 13114224013313. The reversal of 13114224013307 is 70331042241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13114224013307 - 216 = 13114223947771 is a prime.
It is not a weakly prime, because it can be changed into another prime (13114224015307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557112006653 + 6557112006654.
It is an arithmetic number, because the mean of its divisors is an integer number (6557112006654).
Almost surely, 213114224013307 is an apocalyptic number.
13114224013307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13114224013307 is an equidigital number, since it uses as much as digits as its factorization.
13114224013307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13114224013307 its reverse (70331042241131), we get a palindrome (83445266254438).
The spelling of 13114224013307 in words is "thirteen trillion, one hundred fourteen billion, two hundred twenty-four million, thirteen thousand, three hundred seven".
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