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1311422535233 is a prime number
BaseRepresentation
bin10011000101010110110…
…111111101011001000001
311122101000021212100211122
4103011112313331121001
5132441243132111413
62442243104122025
7163514162424356
oct23052667753101
94571007770748
101311422535233
11466197917a58
121921b4906315
1396888723725
144768a60862d
15241a6b2a108
hex13156dfd641

1311422535233 has 2 divisors, whose sum is σ = 1311422535234. Its totient is φ = 1311422535232.

The previous prime is 1311422535217. The next prime is 1311422535239. The reversal of 1311422535233 is 3325352241131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 878600651569 + 432821883664 = 937337^2 + 657892^2 .

It is an emirp because it is prime and its reverse (3325352241131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311422535233 - 24 = 1311422535217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311422535193 and 1311422535202.

It is not a weakly prime, because it can be changed into another prime (1311422535239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655711267616 + 655711267617.

It is an arithmetic number, because the mean of its divisors is an integer number (655711267617).

Almost surely, 21311422535233 is an apocalyptic number.

It is an amenable number.

1311422535233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311422535233 is an equidigital number, since it uses as much as digits as its factorization.

1311422535233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 64800, while the sum is 35.

Adding to 1311422535233 its reverse (3325352241131), we get a palindrome (4636774776364).

The spelling of 1311422535233 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred thirty-five thousand, two hundred thirty-three".