13114234204121 has 4 divisors (see below), whose sum is σ = 13116254582544. Its totient is φ = 13112213825700.

The previous prime is 13114234204091. The next prime is 13114234204163. The reversal of 13114234204121 is 12140243241131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13114234204121 - 2¹⁰ = 13114234203097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13114234224121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1010179475 + ... + 1010192456.

It is an arithmetic number, because the mean of its divisors is an integer number (3279063645636).

Almost surely, 2^{13114234204121} is an apocalyptic number.

It is an amenable number.

13114234204121 is a deficient number, since it is larger than the sum of its proper divisors (2020378423).

13114234204121 is an equidigital number, since it uses as much as digits as its factorization.

13114234204121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2020378422.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 13114234204121 its reverse (12140243241131), we get a palindrome (25254477445252).

The spelling of 13114234204121 in words is "thirteen trillion, one hundred fourteen billion, two hundred thirty-four million, two hundred four thousand, one hundred twenty-one".