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13114240021331 is a prime number
BaseRepresentation
bin1011111011010110010110…
…0111100011001101010011
31201102201010221020220110122
42332311211213203031103
53204330430421140311
643520333152420455
72522321043640151
oct276654547431523
951381127226418
1013114240021331
1141a6799671669
12157976454772b
1374188a734487
14334a3839c3d1
1517b1e8b170db
hexbed659e3353

13114240021331 has 2 divisors, whose sum is σ = 13114240021332. Its totient is φ = 13114240021330.

The previous prime is 13114240021303. The next prime is 13114240021367. The reversal of 13114240021331 is 13312004241131.

It is a weak prime.

It is an emirp because it is prime and its reverse (13312004241131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13114240021331 is a prime.

It is a super-2 number, since 2×131142400213312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13114240021331.

It is not a weakly prime, because it can be changed into another prime (13114240021301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557120010665 + 6557120010666.

It is an arithmetic number, because the mean of its divisors is an integer number (6557120010666).

Almost surely, 213114240021331 is an apocalyptic number.

13114240021331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114240021331 is an equidigital number, since it uses as much as digits as its factorization.

13114240021331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 13114240021331 its reverse (13312004241131), we get a palindrome (26426244262462).

The spelling of 13114240021331 in words is "thirteen trillion, one hundred fourteen billion, two hundred forty million, twenty-one thousand, three hundred thirty-one".