Base | Representation |
---|---|
bin | 11101110100010111111000… |
… | …110110010010100110110010 |
3 | 122012100002111010122221112012 |
4 | 131310113320312102212302 |
5 | 114142114124311232242 |
6 | 1142525554143402522 |
7 | 36423504131511065 |
oct | 3564277066224662 |
9 | 565302433587465 |
10 | 131142411430322 |
11 | 38871203416586 |
12 | 128603402b3442 |
13 | 58238a3ba1256 |
14 | 24554801ca8dc |
15 | 10264ad5b4282 |
hex | 7745f8d929b2 |
131142411430322 has 4 divisors (see below), whose sum is σ = 196713617145486. Its totient is φ = 65571205715160.
The previous prime is 131142411430271. The next prime is 131142411430333. The reversal of 131142411430322 is 223034114241131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 130361840947321 + 780570483001 = 11417611^2 + 883499^2 .
It is a super-2 number, since 2×1311424114303222 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785602857579 + ... + 32785602857582.
Almost surely, 2131142411430322 is an apocalyptic number.
131142411430322 is a deficient number, since it is larger than the sum of its proper divisors (65571205715164).
131142411430322 is an equidigital number, since it uses as much as digits as its factorization.
131142411430322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65571205715163.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 131142411430322 its reverse (223034114241131), we get a palindrome (354176525671453).
The spelling of 131142411430322 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred eleven million, four hundred thirty thousand, three hundred twenty-two".
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