Base | Representation |
---|---|
bin | 11101110100010111111001… |
… | …011111010100111011010011 |
3 | 122012100002111212220110220202 |
4 | 131310113321133110323103 |
5 | 114142114140040001411 |
6 | 1142525555210125415 |
7 | 36423504322113563 |
oct | 3564277137247323 |
9 | 565302455813822 |
10 | 131142422187731 |
11 | 388712094a37a9 |
12 | 12860343a2086b |
13 | 58238a6199796 |
14 | 24554817cada3 |
15 | 10264ae4db83b |
hex | 7745f97d4ed3 |
131142422187731 has 2 divisors, whose sum is σ = 131142422187732. Its totient is φ = 131142422187730.
The previous prime is 131142422187703. The next prime is 131142422187739. The reversal of 131142422187731 is 137781224241131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131142422187731 is a prime.
It is a super-2 number, since 2×1311424221877312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131142422187739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571211093865 + 65571211093866.
It is an arithmetic number, because the mean of its divisors is an integer number (65571211093866).
Almost surely, 2131142422187731 is an apocalyptic number.
131142422187731 is a deficient number, since it is larger than the sum of its proper divisors (1).
131142422187731 is an equidigital number, since it uses as much as digits as its factorization.
131142422187731 is an evil number, because the sum of its binary digits is even.
The product of its digits is 451584, while the sum is 47.
The spelling of 131142422187731 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-two million, one hundred eighty-seven thousand, seven hundred thirty-one".
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