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131142422204707 is a prime number
BaseRepresentation
bin11101110100010111111001…
…011111011001000100100011
3122012100002111212221100012111
4131310113321133121010203
5114142114140041022312
61142525555210340151
736423504322214224
oct3564277137310443
9565302455840174
10131142422204707
1138871209505531
1212860343a2a657
1358238a61a4424
1424554817d324b
1510264ae4e18a7
hex7745f97d9123

131142422204707 has 2 divisors, whose sum is σ = 131142422204708. Its totient is φ = 131142422204706.

The previous prime is 131142422204653. The next prime is 131142422204831. The reversal of 131142422204707 is 707402224241131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131142422204707 - 215 = 131142422171939 is a prime.

It is a super-2 number, since 2×1311424222047072 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131142422204707.

It is not a weakly prime, because it can be changed into another prime (131142422804707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65571211102353 + 65571211102354.

It is an arithmetic number, because the mean of its divisors is an integer number (65571211102354).

Almost surely, 2131142422204707 is an apocalyptic number.

131142422204707 is a deficient number, since it is larger than the sum of its proper divisors (1).

131142422204707 is an equidigital number, since it uses as much as digits as its factorization.

131142422204707 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150528, while the sum is 40.

Adding to 131142422204707 its reverse (707402224241131), we get a palindrome (838544646445838).

The spelling of 131142422204707 in words is "one hundred thirty-one trillion, one hundred forty-two billion, four hundred twenty-two million, two hundred four thousand, seven hundred seven".