Base | Representation |
---|---|
bin | 10011000101010111001… |
… | …000101111000111010011 |
3 | 11122101000121010210201102 |
4 | 103011113020233013103 |
5 | 132441300243330303 |
6 | 2442243342255015 |
7 | 163514245002422 |
oct | 23052710570723 |
9 | 4571017123642 |
10 | 1311426933203 |
11 | 46619a351242 |
12 | 1921b628746b |
13 | 9688960348a |
14 | 4768b0312b9 |
15 | 241a71e8288 |
hex | 1315722f1d3 |
1311426933203 has 2 divisors, whose sum is σ = 1311426933204. Its totient is φ = 1311426933202.
The previous prime is 1311426933133. The next prime is 1311426933247. The reversal of 1311426933203 is 3023396241131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311426933203 - 236 = 1242707456467 is a prime.
It is a super-2 number, since 2×13114269332032 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1311426903203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655713466601 + 655713466602.
It is an arithmetic number, because the mean of its divisors is an integer number (655713466602).
Almost surely, 21311426933203 is an apocalyptic number.
1311426933203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311426933203 is an equidigital number, since it uses as much as digits as its factorization.
1311426933203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 38.
The spelling of 1311426933203 in words is "one trillion, three hundred eleven billion, four hundred twenty-six million, nine hundred thirty-three thousand, two hundred three".
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