131143113505553 has 4 divisors (see below), whose sum is σ = 131143170160368. Its totient is φ = 131143056850740.

The previous prime is 131143113505541. The next prime is 131143113505597. The reversal of 131143113505553 is 355505311341131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131143113505553 - 2²⁶ = 131143046396689 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131143113505553.

It is not an unprimeable number, because it can be changed into a prime (131143113505253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24700451 + ... + 29536392.

It is an arithmetic number, because the mean of its divisors is an integer number (32785792540092).

Almost surely, 2^{131143113505553} is an apocalyptic number.

It is an amenable number.

131143113505553 is a deficient number, since it is larger than the sum of its proper divisors (56654815).

131143113505553 is an equidigital number, since it uses as much as digits as its factorization.

131143113505553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56654814.

The product of its (nonzero) digits is 202500, while the sum is 41.

Adding to 131143113505553 its reverse (355505311341131), we get a palindrome (486648424846684).

The spelling of 131143113505553 in words is "one hundred thirty-one trillion, one hundred forty-three billion, one hundred thirteen million, five hundred five thousand, five hundred fifty-three".