Base | Representation |
---|---|
bin | 10011000101010111011… |
… | …100010001101011111111 |
3 | 11122101000221210001021000 |
4 | 103011113130101223333 |
5 | 132441303101234201 |
6 | 2442244044141343 |
7 | 163514336355402 |
oct | 23052734215377 |
9 | 4571027701230 |
10 | 1311432055551 |
11 | 4661a222a792 |
12 | 1921b7b37853 |
13 | 9688a6a7b57 |
14 | 4768b9a5d39 |
15 | 241a78aad86 |
hex | 13157711aff |
1311432055551 has 32 divisors (see below), whose sum is σ = 2013806808000. Its totient is φ = 842481489024.
The previous prime is 1311432055543. The next prime is 1311432055553. The reversal of 1311432055551 is 1555502341131.
1311432055551 is a `hidden beast` number, since 1 + 3 + 11 + 43 + 2 + 0 + 55 + 551 = 666.
It is not a de Polignac number, because 1311432055551 - 23 = 1311432055543 is a prime.
It is a super-2 number, since 2×13114320555512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311432055553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1246720 + ... + 2043813.
It is an arithmetic number, because the mean of its divisors is an integer number (62931462750).
Almost surely, 21311432055551 is an apocalyptic number.
1311432055551 is a deficient number, since it is larger than the sum of its proper divisors (702374752449).
1311432055551 is a wasteful number, since it uses less digits than its factorization.
1311432055551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3291080 (or 3291074 counting only the distinct ones).
The product of its (nonzero) digits is 45000, while the sum is 36.
Adding to 1311432055551 its reverse (1555502341131), we get a palindrome (2866934396682).
The spelling of 1311432055551 in words is "one trillion, three hundred eleven billion, four hundred thirty-two million, fifty-five thousand, five hundred fifty-one".
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