Base | Representation |
---|---|
bin | 11101110100011000101000… |
… | …101001010001011011100011 |
3 | 122012100011120000120100212011 |
4 | 131310120220221101123203 |
5 | 114142122300102332003 |
6 | 1142530205511013351 |
7 | 36423533036502406 |
oct | 3564305051213343 |
9 | 565304500510764 |
10 | 131143213324003 |
11 | 38871585030131 |
12 | 1286052496a257 |
13 | 58239a106805a |
14 | 24555188c9d3d |
15 | 1026508bb246d |
hex | 774628a516e3 |
131143213324003 has 16 divisors (see below), whose sum is σ = 134745696938560. Its totient is φ = 127543797058176.
The previous prime is 131143213323943. The next prime is 131143213324033. The reversal of 131143213324003 is 300423312341131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131143213324003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131143213324033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 931523125 + ... + 931663897.
It is an arithmetic number, because the mean of its divisors is an integer number (8421606058660).
Almost surely, 2131143213324003 is an apocalyptic number.
131143213324003 is a deficient number, since it is larger than the sum of its proper divisors (3602483614557).
131143213324003 is a wasteful number, since it uses less digits than its factorization.
131143213324003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151486.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 131143213324003 its reverse (300423312341131), we get a palindrome (431566525665134).
The spelling of 131143213324003 in words is "one hundred thirty-one trillion, one hundred forty-three billion, two hundred thirteen million, three hundred twenty-four thousand, three".
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