13114334014233 has 8 divisors (see below), whose sum is σ = 17488585867200. Its totient is φ = 8741485752048.

The previous prime is 13114334014213. The next prime is 13114334014273. The reversal of 13114334014233 is 33241043341131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-13114334014233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114334014194 and 13114334014203.

It is not an unprimeable number, because it can be changed into a prime (13114334014213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 350875893 + ... + 350913266.

It is an arithmetic number, because the mean of its divisors is an integer number (2186073233400).

Almost surely, 2^{13114334014233} is an apocalyptic number.

It is an amenable number.

13114334014233 is a deficient number, since it is larger than the sum of its proper divisors (4374251852967).

13114334014233 is an equidigital number, since it uses as much as digits as its factorization.

13114334014233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 701795391.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 13114334014233 its reverse (33241043341131), we get a palindrome (46355377355364).

The spelling of 13114334014233 in words is "thirteen trillion, one hundred fourteen billion, three hundred thirty-four million, fourteen thousand, two hundred thirty-three".