1311436406233 has 4 divisors (see below), whose sum is σ = 1311660857808. Its totient is φ = 1311211954660.

The previous prime is 1311436406201. The next prime is 1311436406239. The reversal of 1311436406233 is 3326046341131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311436406233 - 2⁵ = 1311436406201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311436406192 and 1311436406201.

It is not an unprimeable number, because it can be changed into a prime (1311436406239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112217023 + ... + 112228708.

It is an arithmetic number, because the mean of its divisors is an integer number (327915214452).

Almost surely, 2^{1311436406233} is an apocalyptic number.

It is an amenable number.

1311436406233 is a deficient number, since it is larger than the sum of its proper divisors (224451575).

1311436406233 is an equidigital number, since it uses as much as digits as its factorization.

1311436406233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 224451574.

The product of its (nonzero) digits is 93312, while the sum is 37.

The spelling of 1311436406233 in words is "one trillion, three hundred eleven billion, four hundred thirty-six million, four hundred six thousand, two hundred thirty-three".