Base | Representation |
---|---|
bin | 10011000101010111101… |
… | …100111001000100001011 |
3 | 11122101001020222100000101 |
4 | 103011113230321010023 |
5 | 132441310210124042 |
6 | 2442244321350231 |
7 | 163514421366052 |
oct | 23052754710413 |
9 | 4571036870011 |
10 | 1311436411147 |
11 | 4661a4735155 |
12 | 1921b9498377 |
13 | 9688b571525 |
14 | 4768c3bb399 |
15 | 241a7e6b6b7 |
hex | 13157b3910b |
1311436411147 has 2 divisors, whose sum is σ = 1311436411148. Its totient is φ = 1311436411146.
The previous prime is 1311436411093. The next prime is 1311436411163. The reversal of 1311436411147 is 7411146341131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1311436411147 - 223 = 1311428022539 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311436412147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655718205573 + 655718205574.
It is an arithmetic number, because the mean of its divisors is an integer number (655718205574).
Almost surely, 21311436411147 is an apocalyptic number.
1311436411147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311436411147 is an equidigital number, since it uses as much as digits as its factorization.
1311436411147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24192, while the sum is 37.
The spelling of 1311436411147 in words is "one trillion, three hundred eleven billion, four hundred thirty-six million, four hundred eleven thousand, one hundred forty-seven".
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