13114401333041 has 2 divisors, whose sum is σ = 13114401333042. Its totient is φ = 13114401333040.

The previous prime is 13114401333001. The next prime is 13114401333049. The reversal of 13114401333041 is 14033310441131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11757327778816 + 1357073554225 = 3428896^2 + 1164935^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13114401333041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13114401332995 and 13114401333013.

It is not a weakly prime, because it can be changed into another prime (13114401333049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557200666520 + 6557200666521.

It is an arithmetic number, because the mean of its divisors is an integer number (6557200666521).

Almost surely, 2^{13114401333041} is an apocalyptic number.

It is an amenable number.

13114401333041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13114401333041 is an equidigital number, since it uses as much as digits as its factorization.

13114401333041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13114401333041 its reverse (14033310441131), we get a palindrome (27147711774172).

The spelling of 13114401333041 in words is "thirteen trillion, one hundred fourteen billion, four hundred one million, three hundred thirty-three thousand, forty-one".