13114441243441 has 4 divisors (see below), whose sum is σ = 13115386578532. Its totient is φ = 13113495908352.

The previous prime is 13114441243439. The next prime is 13114441243481. The reversal of 13114441243441 is 14434214441131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3613405602816 + 9501035640625 = 1900896^2 + 3082375^2 .

It is a cyclic number.

It is not a de Polignac number, because 13114441243441 - 2¹ = 13114441243439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13114441243441.

It is not an unprimeable number, because it can be changed into a prime (13114441243481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 472646736 + ... + 472674481.

It is an arithmetic number, because the mean of its divisors is an integer number (3278846644633).

Almost surely, 2^{13114441243441} is an apocalyptic number.

It is an amenable number.

13114441243441 is a deficient number, since it is larger than the sum of its proper divisors (945335091).

13114441243441 is an equidigital number, since it uses as much as digits as its factorization.

13114441243441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 945335090.

The product of its digits is 73728, while the sum is 37.

Adding to 13114441243441 its reverse (14434214441131), we get a palindrome (27548655684572).

The spelling of 13114441243441 in words is "thirteen trillion, one hundred fourteen billion, four hundred forty-one million, two hundred forty-three thousand, four hundred forty-one".