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131148331 is a prime number
BaseRepresentation
bin1111101000100…
…10101000101011
3100010210000200121
413310102220223
5232033221311
621002544111
73151512436
oct764225053
9303700617
10131148331
1168036756
1237b08037
132122b382
14135bc81d
15b7a8b71
hex7d12a2b

131148331 has 2 divisors, whose sum is σ = 131148332. Its totient is φ = 131148330.

The previous prime is 131148293. The next prime is 131148343. The reversal of 131148331 is 133841131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131148331 - 215 = 131115563 is a prime.

It is a super-2 number, since 2×1311483312 = 34399769448171122, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131148296 and 131148305.

It is not a weakly prime, because it can be changed into another prime (131148361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65574165 + 65574166.

It is an arithmetic number, because the mean of its divisors is an integer number (65574166).

Almost surely, 2131148331 is an apocalyptic number.

131148331 is a deficient number, since it is larger than the sum of its proper divisors (1).

131148331 is an equidigital number, since it uses as much as digits as its factorization.

131148331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 864, while the sum is 25.

The square root of 131148331 is about 11452.0011788333. The cubic root of 131148331 is about 508.0669241919.

Adding to 131148331 its reverse (133841131), we get a palindrome (264989462).

The spelling of 131148331 in words is "one hundred thirty-one million, one hundred forty-eight thousand, three hundred thirty-one".