1311501501553 has 4 divisors (see below), whose sum is σ = 1323758525040. Its totient is φ = 1299244478068.

The previous prime is 1311501501521. The next prime is 1311501501577. The reversal of 1311501501553 is 3551051051131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311501501553 - 2⁵ = 1311501501521 is a prime.

It is a super-2 number, since 2×1311501501553² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311501505553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6128511583 + ... + 6128511796.

It is an arithmetic number, because the mean of its divisors is an integer number (330939631260).

Almost surely, 2^{1311501501553} is an apocalyptic number.

It is an amenable number.

1311501501553 is a deficient number, since it is larger than the sum of its proper divisors (12257023487).

1311501501553 is a wasteful number, since it uses less digits than its factorization.

1311501501553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12257023486.

The product of its (nonzero) digits is 5625, while the sum is 31.

Adding to 1311501501553 its reverse (3551051051131), we get a palindrome (4862552552684).

The spelling of 1311501501553 in words is "one trillion, three hundred eleven billion, five hundred one million, five hundred one thousand, five hundred fifty-three".