Base | Representation |
---|---|
bin | 111101000100100101… |
… | …0011001000010001011 |
3 | 110112112002021112211022 |
4 | 1322021022121002023 |
5 | 4122043424041301 |
6 | 140125524223055 |
7 | 12322011326444 |
oct | 1721112310213 |
9 | 415462245738 |
10 | 131150221451 |
11 | 50690976577 |
12 | 21501b3aa8b |
13 | c4a128a642 |
14 | 64c215c2cb |
15 | 3628d19d1b |
hex | 1e8929908b |
131150221451 has 4 divisors (see below), whose sum is σ = 131151382152. Its totient is φ = 131149060752.
The previous prime is 131150221429. The next prime is 131150221457. The reversal of 131150221451 is 154122051131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131150221451 - 218 = 131149959307 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131150221451.
It is not an unprimeable number, because it can be changed into a prime (131150221457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390065 + ... + 643778.
It is an arithmetic number, because the mean of its divisors is an integer number (32787845538).
Almost surely, 2131150221451 is an apocalyptic number.
131150221451 is a deficient number, since it is larger than the sum of its proper divisors (1160701).
131150221451 is a wasteful number, since it uses less digits than its factorization.
131150221451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1160700.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 131150221451 its reverse (154122051131), we get a palindrome (285272272582).
The spelling of 131150221451 in words is "one hundred thirty-one billion, one hundred fifty million, two hundred twenty-one thousand, four hundred fifty-one".
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