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131150221451 = 1268571033843
BaseRepresentation
bin111101000100100101…
…0011001000010001011
3110112112002021112211022
41322021022121002023
54122043424041301
6140125524223055
712322011326444
oct1721112310213
9415462245738
10131150221451
1150690976577
1221501b3aa8b
13c4a128a642
1464c215c2cb
153628d19d1b
hex1e8929908b

131150221451 has 4 divisors (see below), whose sum is σ = 131151382152. Its totient is φ = 131149060752.

The previous prime is 131150221429. The next prime is 131150221457. The reversal of 131150221451 is 154122051131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131150221451 - 218 = 131149959307 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131150221451.

It is not an unprimeable number, because it can be changed into a prime (131150221457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390065 + ... + 643778.

It is an arithmetic number, because the mean of its divisors is an integer number (32787845538).

Almost surely, 2131150221451 is an apocalyptic number.

131150221451 is a deficient number, since it is larger than the sum of its proper divisors (1160701).

131150221451 is a wasteful number, since it uses less digits than its factorization.

131150221451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1160700.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 131150221451 its reverse (154122051131), we get a palindrome (285272272582).

The spelling of 131150221451 in words is "one hundred thirty-one billion, one hundred fifty million, two hundred twenty-one thousand, four hundred fifty-one".

Divisors: 1 126857 1033843 131150221451