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13115040000 = 2835489307
BaseRepresentation
bin11000011011011011…
…11010000100000000
31020212000021001200020
430031231322010000
5203324422240000
610005220453440
7643001000136
oct141555720400
936760231606
1013115040000
115620109737
12266024a280
1313101800ca
148c5b53756
1551b5c7ba0
hex30db7a100

13115040000 has 360 divisors, whose sum is σ = 44251210080. Its totient is φ = 3446784000.

The previous prime is 13115039957. The next prime is 13115040023. The reversal of 13115040000 is 4051131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 42719847 + ... + 42720153.

It is an arithmetic number, because the mean of its divisors is an integer number (122920028).

Almost surely, 213115040000 is an apocalyptic number.

13115040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13115040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22125605040).

13115040000 is an abundant number, since it is smaller than the sum of its proper divisors (31136170080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13115040000 is an frugal number, since it uses more digits than its factorization.

13115040000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 435 (or 406 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 13115040000 its reverse (4051131), we get a palindrome (13119091131).

The spelling of 13115040000 in words is "thirteen billion, one hundred fifteen million, forty thousand".