Base | Representation |
---|---|
bin | 11000011011011100… |
… | …10101000001000001 |
3 | 1020212000110200010011 |
4 | 30031232111001001 |
5 | 203324434303101 |
6 | 10005223104521 |
7 | 643001640043 |
oct | 141556250101 |
9 | 36760420104 |
10 | 13115150401 |
11 | 5620184681 |
12 | 26602a2141 |
13 | 13101bb432 |
14 | 8c5b81a93 |
15 | 51b5ea751 |
hex | 30db95041 |
13115150401 has 2 divisors, whose sum is σ = 13115150402. Its totient is φ = 13115150400.
The previous prime is 13115150341. The next prime is 13115150417. The reversal of 13115150401 is 10405151131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11746224400 + 1368926001 = 108380^2 + 36999^2 .
It is an emirp because it is prime and its reverse (10405151131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13115150401 - 215 = 13115117633 is a prime.
It is not a weakly prime, because it can be changed into another prime (13115150491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6557575200 + 6557575201.
It is an arithmetic number, because the mean of its divisors is an integer number (6557575201).
Almost surely, 213115150401 is an apocalyptic number.
It is an amenable number.
13115150401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13115150401 is an equidigital number, since it uses as much as digits as its factorization.
13115150401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 22.
The spelling of 13115150401 in words is "thirteen billion, one hundred fifteen million, one hundred fifty thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •