Base | Representation |
---|---|
bin | 1111101000100… |
… | …11100011010001 |
3 | 100010210012211111 |
4 | 13310103203101 |
5 | 232033331311 |
6 | 21003013321 |
7 | 3151526404 |
oct | 764234321 |
9 | 303705744 |
10 | 131152081 |
11 | 68039555 |
12 | 37b0a241 |
13 | 2122cca8 |
14 | 135bdd3b |
15 | b7a9d21 |
hex | 7d138d1 |
131152081 has 2 divisors, whose sum is σ = 131152082. Its totient is φ = 131152080.
The previous prime is 131152069. The next prime is 131152111. The reversal of 131152081 is 180251131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96530625 + 34621456 = 9825^2 + 5884^2 .
It is a cyclic number.
It is not a de Polignac number, because 131152081 - 221 = 129054929 is a prime.
It is a super-2 number, since 2×1311520812 = 34401736701261122, which contains 22 as substring.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131152001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65576040 + 65576041.
It is an arithmetic number, because the mean of its divisors is an integer number (65576041).
Almost surely, 2131152081 is an apocalyptic number.
It is an amenable number.
131152081 is a deficient number, since it is larger than the sum of its proper divisors (1).
131152081 is an equidigital number, since it uses as much as digits as its factorization.
131152081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 22.
The square root of 131152081 is about 11452.1649045060. The cubic root of 131152081 is about 508.0717666294.
The spelling of 131152081 in words is "one hundred thirty-one million, one hundred fifty-two thousand, eighty-one".
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