Base | Representation |
---|---|
bin | 11101110100100000111100… |
… | …011100101011110110000010 |
3 | 122012101000120211020000211210 |
4 | 131310200330130223312002 |
5 | 114142244033142100414 |
6 | 1142534243112150550 |
7 | 36424300115664636 |
oct | 3564407434536602 |
9 | 565330524200753 |
10 | 131152135503234 |
11 | 388753433a947a |
12 | 128621b4998456 |
13 | 582479366bb51 |
14 | 2455b23844dc6 |
15 | 102687c11ae59 |
hex | 77483c72bd82 |
131152135503234 has 32 divisors (see below), whose sum is σ = 271351155539520. Its totient is φ = 42209585630912.
The previous prime is 131152135503211. The next prime is 131152135503251. The reversal of 131152135503234 is 432305531251131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 131152135503192 and 131152135503201.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22845097 + ... + 28003619.
It is an arithmetic number, because the mean of its divisors is an integer number (8479723610610).
Almost surely, 2131152135503234 is an apocalyptic number.
131152135503234 is an abundant number, since it is smaller than the sum of its proper divisors (140199020036286).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131152135503234 is a wasteful number, since it uses less digits than its factorization.
131152135503234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5304674.
The product of its (nonzero) digits is 162000, while the sum is 39.
Adding to 131152135503234 its reverse (432305531251131), we get a palindrome (563457666754365).
The spelling of 131152135503234 in words is "one hundred thirty-one trillion, one hundred fifty-two billion, one hundred thirty-five million, five hundred three thousand, two hundred thirty-four".
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