131153140125041 has 8 divisors (see below), whose sum is σ = 131532749846400. Its totient is φ = 130773552191568.

The previous prime is 131153140125031. The next prime is 131153140125079. The reversal of 131153140125041 is 140521041351131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131153140125041 - 2³⁴ = 131135960255857 is a prime.

It is a super-2 number, since 2×131153140125041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131153140124989 and 131153140125007.

It is not an unprimeable number, because it can be changed into a prime (131153140125001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6648350 + ... + 17507336.

It is an arithmetic number, because the mean of its divisors is an integer number (16441593730800).

Almost surely, 2^{131153140125041} is an apocalyptic number.

It is an amenable number.

131153140125041 is a deficient number, since it is larger than the sum of its proper divisors (379609721359).

131153140125041 is a wasteful number, since it uses less digits than its factorization.

131153140125041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10893943.

The product of its (nonzero) digits is 7200, while the sum is 32.

Adding to 131153140125041 its reverse (140521041351131), we get a palindrome (271674181476172).

The spelling of 131153140125041 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, one hundred forty million, one hundred twenty-five thousand, forty-one".