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131153142917089 is a prime number
BaseRepresentation
bin11101110100100001111000…
…011111101010011111100001
3122012101010012000211221212001
4131310201320133222133201
5114142303114041321324
61142534531100404001
736424334100604366
oct3564417037523741
9565333160757761
10131153142917089
1138875810026407
1212862436246601
1358248c42a3717
142455bbb56246d
1510268da7b3e44
hex7748787ea7e1

131153142917089 has 2 divisors, whose sum is σ = 131153142917090. Its totient is φ = 131153142917088.

The previous prime is 131153142917039. The next prime is 131153142917119. The reversal of 131153142917089 is 980719241351131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122994310478400 + 8158832438689 = 11090280^2 + 2856367^2 .

It is a cyclic number.

It is not a de Polignac number, because 131153142917089 - 233 = 131144552982497 is a prime.

It is a super-2 number, since 2×1311531429170892 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131153142917039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65576571458544 + 65576571458545.

It is an arithmetic number, because the mean of its divisors is an integer number (65576571458545).

Almost surely, 2131153142917089 is an apocalyptic number.

It is an amenable number.

131153142917089 is a deficient number, since it is larger than the sum of its proper divisors (1).

131153142917089 is an equidigital number, since it uses as much as digits as its factorization.

131153142917089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1632960, while the sum is 55.

It can be divided in two parts, 131153142 and 917089, that added together give a palindrome (132070231).

The spelling of 131153142917089 in words is "one hundred thirty-one trillion, one hundred fifty-three billion, one hundred forty-two million, nine hundred seventeen thousand, eighty-nine".