131153403 has 4 divisors (see below), whose sum is σ = 174871208. Its totient is φ = 87435600.

The previous prime is 131153389. The next prime is 131153411. The reversal of 131153403 is 304351131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131153403 - 2⁴ = 131153387 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131153403.

It is not an unprimeable number, because it can be changed into a prime (131153413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21858898 + ... + 21858903.

It is an arithmetic number, because the mean of its divisors is an integer number (43717802).

Almost surely, 2^131153403 is an apocalyptic number.

131153403 is a deficient number, since it is larger than the sum of its proper divisors (43717805).

131153403 is an equidigital number, since it uses as much as digits as its factorization.

131153403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43717804.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 131153403 is about 11452.2226227052. Note that the first 3 decimals coincide. The cubic root of 131153403 is about 508.0734737280.

The spelling of 131153403 in words is "one hundred thirty-one million, one hundred fifty-three thousand, four hundred three".