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1311535424273 is a prime number
BaseRepresentation
bin10011000101011101100…
…110100110001100010001
311122101022011021201111012
4103011131212212030101
5132442011032034043
62442302215500305
7163520033111054
oct23053546461421
94571264251435
101311535424273
11466245612188
12192226687695
13968a5c2aa89
144769b5d2a9b
15241b19c8a18
hex1315d9a6311

1311535424273 has 2 divisors, whose sum is σ = 1311535424274. Its totient is φ = 1311535424272.

The previous prime is 1311535424239. The next prime is 1311535424413. The reversal of 1311535424273 is 3724245351131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1292116444369 + 19418979904 = 1136713^2 + 139352^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311535424273 - 212 = 1311535420177 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1311535424273.

It is not a weakly prime, because it can be changed into another prime (1311535424233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655767712136 + 655767712137.

It is an arithmetic number, because the mean of its divisors is an integer number (655767712137).

Almost surely, 21311535424273 is an apocalyptic number.

It is an amenable number.

1311535424273 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311535424273 is an equidigital number, since it uses as much as digits as its factorization.

1311535424273 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 302400, while the sum is 41.

The spelling of 1311535424273 in words is "one trillion, three hundred eleven billion, five hundred thirty-five million, four hundred twenty-four thousand, two hundred seventy-three".