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131153554043 = 612150058263
BaseRepresentation
bin111101000100101011…
…1000110101001111011
3110112112022112212021122
41322021113012221323
54122100302212133
6140130123455455
712322051546451
oct1721127065173
9415468485248
10131153554043
1150692842386
122150308758b
13c4a1b864a5
1464c27889d1
153629277498
hex1e895c6a7b

131153554043 has 4 divisors (see below), whose sum is σ = 133303612368. Its totient is φ = 129003495720.

The previous prime is 131153554039. The next prime is 131153554061. The reversal of 131153554043 is 340455351131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 340455351131 = 748636478733.

It is a cyclic number.

It is not a de Polignac number, because 131153554043 - 22 = 131153554039 is a prime.

It is a super-2 number, since 2×1311535540432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131153553994 and 131153554012.

It is not an unprimeable number, because it can be changed into a prime (131153550043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1075029071 + ... + 1075029192.

It is an arithmetic number, because the mean of its divisors is an integer number (33325903092).

Almost surely, 2131153554043 is an apocalyptic number.

131153554043 is a deficient number, since it is larger than the sum of its proper divisors (2150058325).

131153554043 is an equidigital number, since it uses as much as digits as its factorization.

131153554043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2150058324.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 131153554043 in words is "one hundred thirty-one billion, one hundred fifty-three million, five hundred fifty-four thousand, forty-three".

Divisors: 1 61 2150058263 131153554043