1311541040353 has 4 divisors (see below), whose sum is σ = 1314373742848. Its totient is φ = 1308708337860.

The previous prime is 1311541040347. The next prime is 1311541040357. The reversal of 1311541040353 is 3530401451131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311541040353 - 2⁵ = 1311541040321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311541040357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1416350553 + ... + 1416351478.

It is an arithmetic number, because the mean of its divisors is an integer number (328593435712).

Almost surely, 2^{1311541040353} is an apocalyptic number.

It is an amenable number.

1311541040353 is a deficient number, since it is larger than the sum of its proper divisors (2832702495).

1311541040353 is an equidigital number, since it uses as much as digits as its factorization.

1311541040353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2832702494.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1311541040353 its reverse (3530401451131), we get a palindrome (4841942491484).

The spelling of 1311541040353 in words is "one trillion, three hundred eleven billion, five hundred forty-one million, forty thousand, three hundred fifty-three".