Base | Representation |
---|---|
bin | 10011000101100001101… |
… | …101011001000010000010 |
3 | 11122101110221220200202112 |
4 | 103011201231121002002 |
5 | 132442131201023432 |
6 | 2442313120215322 |
7 | 163521530502335 |
oct | 23054155310202 |
9 | 4571427820675 |
10 | 1311604314242 |
11 | 466280495242 |
12 | 19224576a542 |
13 | 968b729b281 |
14 | 476a680661c |
15 | 241b7a857b2 |
hex | 13161b59082 |
1311604314242 has 4 divisors (see below), whose sum is σ = 1967406471366. Its totient is φ = 655802157120.
The previous prime is 1311604314233. The next prime is 1311604314277. The reversal of 1311604314242 is 2424134061131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1070502691801 + 241101622441 = 1034651^2 + 491021^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1311604314199 and 1311604314208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327901078559 + ... + 327901078562.
Almost surely, 21311604314242 is an apocalyptic number.
1311604314242 is a deficient number, since it is larger than the sum of its proper divisors (655802157124).
1311604314242 is an equidigital number, since it uses as much as digits as its factorization.
1311604314242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 655802157123.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 1311604314242 its reverse (2424134061131), we get a palindrome (3735738375373).
The spelling of 1311604314242 in words is "one trillion, three hundred eleven billion, six hundred four million, three hundred fourteen thousand, two hundred forty-two".
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