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1311623041 = 5922230899
BaseRepresentation
bin100111000101101…
…1100011110000001
310101102001100120011
41032023130132001
510141233414131
6334052344521
744334416611
oct11613343601
93342040504
101311623041
11613416893
12307315141
1317b977511
14c62a8a41
157a2390b1
hex4e2dc781

1311623041 has 4 divisors (see below), whose sum is σ = 1333854000. Its totient is φ = 1289392084.

The previous prime is 1311623009. The next prime is 1311623069. The reversal of 1311623041 is 1403261131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311623041 - 25 = 1311623009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311623141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11115391 + ... + 11115508.

It is an arithmetic number, because the mean of its divisors is an integer number (333463500).

Almost surely, 21311623041 is an apocalyptic number.

It is an amenable number.

1311623041 is a deficient number, since it is larger than the sum of its proper divisors (22230959).

1311623041 is an equidigital number, since it uses as much as digits as its factorization.

1311623041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22230958.

The product of its (nonzero) digits is 432, while the sum is 22.

The square root of 1311623041 is about 36216.3366590272. The cubic root of 1311623041 is about 1094.6358792936.

Adding to 1311623041 its reverse (1403261131), we get a palindrome (2714884172).

The spelling of 1311623041 in words is "one billion, three hundred eleven million, six hundred twenty-three thousand, forty-one".

Divisors: 1 59 22230899 1311623041