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1311646317881 is a prime number
BaseRepresentation
bin10011000101100100001…
…101100111110100111001
311122101120212221200220212
4103011210031213310321
5132442222424133011
62442321220400505
7163522550514044
oct23054415476471
94571525850825
101311646317881
114662a2174199
12192257846135
13968c2bb6ab3
14476ac21bc5b
15241bb5d108b
hex13164367d39

1311646317881 has 2 divisors, whose sum is σ = 1311646317882. Its totient is φ = 1311646317880.

The previous prime is 1311646317841. The next prime is 1311646317899. The reversal of 1311646317881 is 1887136461131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 816825518656 + 494820799225 = 903784^2 + 703435^2 .

It is an emirp because it is prime and its reverse (1887136461131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311646317881 is a prime.

It is a super-2 number, since 2×13116463178812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311646317811) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655823158940 + 655823158941.

It is an arithmetic number, because the mean of its divisors is an integer number (655823158941).

Almost surely, 21311646317881 is an apocalyptic number.

It is an amenable number.

1311646317881 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311646317881 is an equidigital number, since it uses as much as digits as its factorization.

1311646317881 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 580608, while the sum is 50.

The spelling of 1311646317881 in words is "one trillion, three hundred eleven billion, six hundred forty-six million, three hundred seventeen thousand, eight hundred eighty-one".