Base | Representation |
---|---|
bin | 1011111011100001000110… |
… | …1100100110001010000011 |
3 | 1201102222121010122220100221 |
4 | 2332320101230212022003 |
5 | 3204402334004302113 |
6 | 43521531443123511 |
7 | 2522452431032251 |
oct | 276702154461203 |
9 | 51388533586327 |
10 | 13117127025283 |
11 | 41a7a40274446 |
12 | 157a22b373597 |
13 | 741c2a8a4a38 |
14 | 334c2d98d5d1 |
15 | 17b3172da98d |
hex | bee11b26283 |
13117127025283 has 2 divisors, whose sum is σ = 13117127025284. Its totient is φ = 13117127025282.
The previous prime is 13117127025241. The next prime is 13117127025371. The reversal of 13117127025283 is 38252072171131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13117127025283 - 217 = 13117126894211 is a prime.
It is not a weakly prime, because it can be changed into another prime (13117127025683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6558563512641 + 6558563512642.
It is an arithmetic number, because the mean of its divisors is an integer number (6558563512642).
Almost surely, 213117127025283 is an apocalyptic number.
13117127025283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13117127025283 is an equidigital number, since it uses as much as digits as its factorization.
13117127025283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 141120, while the sum is 43.
The spelling of 13117127025283 in words is "thirteen trillion, one hundred seventeen billion, one hundred twenty-seven million, twenty-five thousand, two hundred eighty-three".
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