Base | Representation |
---|---|
bin | 1011111011101010010110… |
… | …1111111000010000101001 |
3 | 1201110020000020112111220011 |
4 | 2332322211233320100221 |
5 | 3204422430343220313 |
6 | 43523022133331521 |
7 | 2522601121525654 |
oct | 276724557702051 |
9 | 51406006474804 |
10 | 13119610913833 |
11 | 41a8aa53736a6 |
12 | 157a803196ba1 |
13 | 742235382988 |
14 | 334dc780889b |
15 | 17b4103d293d |
hex | beea5bf8429 |
13119610913833 has 2 divisors, whose sum is σ = 13119610913834. Its totient is φ = 13119610913832.
The previous prime is 13119610913807. The next prime is 13119610913863. The reversal of 13119610913833 is 33831901691131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12392561374249 + 727049539584 = 3520307^2 + 852672^2 .
It is an emirp because it is prime and its reverse (33831901691131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13119610913833 - 233 = 13111020979241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13119610913863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6559805456916 + 6559805456917.
It is an arithmetic number, because the mean of its divisors is an integer number (6559805456917).
Almost surely, 213119610913833 is an apocalyptic number.
It is an amenable number.
13119610913833 is a deficient number, since it is larger than the sum of its proper divisors (1).
13119610913833 is an equidigital number, since it uses as much as digits as its factorization.
13119610913833 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 314928, while the sum is 49.
The spelling of 13119610913833 in words is "thirteen trillion, one hundred nineteen billion, six hundred ten million, nine hundred thirteen thousand, eight hundred thirty-three".
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