Base | Representation |
---|---|
bin | 1011111011101011100000… |
… | …1001101110111111011001 |
3 | 1201110020210202112112111120 |
4 | 2332322320021232333121 |
5 | 3204424043414301442 |
6 | 43523112523315453 |
7 | 2522611561153146 |
oct | 276727011567731 |
9 | 51406722475446 |
10 | 13119919681497 |
11 | 41a9143696392 |
12 | 157a88a67bb89 |
13 | 742284330435 |
14 | 3350168213cd |
15 | 17b42c5744ec |
hex | beeb826efd9 |
13119919681497 has 8 divisors (see below), whose sum is σ = 17496127779840. Its totient is φ = 8745162352080.
The previous prime is 13119919681489. The next prime is 13119919681507. The reversal of 13119919681497 is 79418691991131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13119919681497 - 23 = 13119919681489 is a prime.
It is a super-2 number, since 2×131199196814972 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13119919681457) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 362671129 + ... + 362707302.
It is an arithmetic number, because the mean of its divisors is an integer number (2187015972480).
Almost surely, 213119919681497 is an apocalyptic number.
It is an amenable number.
13119919681497 is a deficient number, since it is larger than the sum of its proper divisors (4376208098343).
13119919681497 is an equidigital number, since it uses as much as digits as its factorization.
13119919681497 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 725384463.
The product of its digits is 26453952, while the sum is 69.
The spelling of 13119919681497 in words is "thirteen trillion, one hundred nineteen billion, nine hundred nineteen million, six hundred eighty-one thousand, four hundred ninety-seven".
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