Base | Representation |
---|---|
bin | 11101110101001110100101… |
… | …011010100101011000111001 |
3 | 122012112201002010002101110021 |
4 | 131311032211122211120321 |
5 | 114144044414121403231 |
6 | 1143012545554250441 |
7 | 36430653405355504 |
oct | 3565164532453071 |
9 | 565481063071407 |
10 | 131201141200441 |
11 | 3889410088a084 |
12 | 1286b7b0886a21 |
13 | 58292a3417910 |
14 | 24582520ac13b |
15 | 1027c99557811 |
hex | 7753a56a5639 |
131201141200441 has 16 divisors (see below), whose sum is σ = 145058379681600. Its totient is φ = 117916624013760.
The previous prime is 131201141200343. The next prime is 131201141200453. The reversal of 131201141200441 is 144002141102131.
It is not a de Polignac number, because 131201141200441 - 213 = 131201141192249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131201141201441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 726713391 + ... + 726893908.
It is an arithmetic number, because the mean of its divisors is an integer number (9066148730100).
Almost surely, 2131201141200441 is an apocalyptic number.
It is an amenable number.
131201141200441 is a deficient number, since it is larger than the sum of its proper divisors (13857238481159).
131201141200441 is a wasteful number, since it uses less digits than its factorization.
131201141200441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1453607496.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 131201141200441 its reverse (144002141102131), we get a palindrome (275203282302572).
The spelling of 131201141200441 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-one million, two hundred thousand, four hundred forty-one".
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