131201141213537 has 2 divisors, whose sum is σ = 131201141213538. Its totient is φ = 131201141213536.

The previous prime is 131201141213413. The next prime is 131201141213551. The reversal of 131201141213537 is 735312141102131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92338435085521 + 38862706128016 = 9609289^2 + 6233996^2 .

It is a cyclic number.

It is not a de Polignac number, because 131201141213537 - 2²² = 131201137019233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131201141213497 and 131201141213506.

It is not a weakly prime, because it can be changed into another prime (131201141813537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600570606768 + 65600570606769.

It is an arithmetic number, because the mean of its divisors is an integer number (65600570606769).

Almost surely, 2^{131201141213537} is an apocalyptic number.

It is an amenable number.

131201141213537 is a deficient number, since it is larger than the sum of its proper divisors (1).

131201141213537 is an equidigital number, since it uses as much as digits as its factorization.

131201141213537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 35.

Adding to 131201141213537 its reverse (735312141102131), we get a palindrome (866513282315668).

The spelling of 131201141213537 in words is "one hundred thirty-one trillion, two hundred one billion, one hundred forty-one million, two hundred thirteen thousand, five hundred thirty-seven".