131201204343434 has 4 divisors (see below), whose sum is σ = 196801806515154. Its totient is φ = 65600602171716.

The previous prime is 131201204343431. The next prime is 131201204343439. The reversal of 131201204343434 is 434343402102131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 131158679717209 + 42524626225 = 11452453^2 + 206215^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131201204343394 and 131201204343403.

It is not an unprimeable number, because it can be changed into a prime (131201204343431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32800301085857 + ... + 32800301085860.

Almost surely, 2^{131201204343434} is an apocalyptic number.

131201204343434 is a deficient number, since it is larger than the sum of its proper divisors (65600602171720).

131201204343434 is an equidigital number, since it uses as much as digits as its factorization.

131201204343434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65600602171719.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 131201204343434 its reverse (434343402102131), we get a palindrome (565544606445565).

The spelling of 131201204343434 in words is "one hundred thirty-one trillion, two hundred one billion, two hundred four million, three hundred forty-three thousand, four hundred thirty-four".